Euler Problem 32 returns to pandigital numbers, which are numbers that contain one of each digit. Like so many of the Euler Problems, these numbers serve no practical purpose whatsoever, just like palindromic products, other than some entertainment value and increasing your understanding of numbers.

You can find all pandigital numbers in base-10 in the Online Encyclopedia of Integers (A050278). The Numberphile video explains everything you ever wanted to know about pandigital numbers but were afraid to ask.

## Euler Problem 32 Definition

We shall say that an *n*-digit number is pandigital if it makes use of all the digits 1 to *n* exactly once; for example, the 5-digit number, 15234, is 1 through 5 pandigital.

The product 7254 is unusual, as the identity, 39 × 186 = 7254, containing multiplicand, multiplier, and product is 1 through 9 pandigital.

Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigital.

HINT: Some products can be obtained in more than one way so be sure to only include it once in your sum.

## Proposed Solution

The `pandigital.9`

function tests whether a string classifies as a pandigital number. The `pandigital.prod`

vector stores the multiplication.

The only way to solve this problem is brute force and try all multiplications but we can limit the solution space to a manageable number. The multiplication needs to have ten digits. For example, when the starting number has two digits, the second number should have three digits so that the total has four digits, e.g.: 39 × 186 = 7254. When the first number only has one digit, the second number needs to have four digits.

You can view the most recent version of this code on GitHub.

pandigital.9 <- function(x) (length(x) == 9 & sum(duplicated(x)) == 0 & sum(x == 0) == 0) t <- proc.time() pandigital.prod <- vector() i <- 1 for (m in 2:100) { if (m < 10) n_start <- 1234 else n_start <- 123 for (n in n_start:round(10000 / m)) { # List of digits digs <- as.numeric(unlist(strsplit(paste0(m, n, m * n), ""))) # is Pandigital? if (pandigital.9(digs)) { pandigital.prod[i] <- m * n i <- i + 1 print(paste(m, "*", n, "=", m * n)) } } } answer <- sum(unique(pandigital.prod)) print(answer)

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